Class X Session 2023-24 Question 28-optional
MATH SAMPLE QUESTION PAPER Class X Session 2023-24 MATHEMATICS STANDARD (Code No.041) Question 28 \[Solve: \; \frac{2}{\sqrt{x}} + \frac{3}{\sqrt{y}} = 2; \frac{4}{\sqrt{x}} - \frac{9}{\sqrt{y}} = -1, x,y>0 \] Explanation: Let's consider : \[a = \; \frac{1}{\sqrt{x}} \; and \; b = \frac{1}{\sqrt{y}} = -1\] Now equation becomes 2a+3b = 2 -----------------(1) 4a - 9b = -1 -------------------------(2) now solve both equations (1) and (2) First, multiply equation (1) by 2 to align the coefficients of a and subtract from each other 2x(2a+3b) - (4a -9b ) = 4 -(-1) \[2\times (2a+3b) - (4a-9b) = 4-(-1)\] \[ or \; 4a+6b -4a + 9b = 4+1\] \[ or \; 15b = 5\] \[ or \; b = \frac{5}{15}\] \[ or \; b = \frac{1}{3}\] Now, substitute b in equation (1) \[\Rightarrow 2a + 3\times \frac{1}{3} = 2\] \[\ or\; 2a + 1 = 2\] \[\ or\; 2a = 1\] \[\therefore a = \frac{1}{2}\] Now we have a and b so we can find the values of x and y \[\ a = \frac{1}{\sqrt{x}} \Rightarrow \frac{1}{2} = \frac{1}{\sqr