lru_cache() reducing the execution time

 Tips: lru_cache on a method uses separate storage for each instance of the class and reduces the execution time. inherited from "functools"

Example 1. 

def increment(num):

    print(f'Running thousands line of code {num}')

    return num + 1

print(increment(1))

print(increment(2))

print(increment(3))

print(increment(1))

output :

Running thousands line of code 1 2 Running thousands line of code 2 3 Running thousands line of code 3 4 Running thousands line of code 1 2

Note : increment(1)

a function is called 2 times at the same time and it could increase the execution

time. and we can reduce the execution time and their process with the help of the

lru_cache method

Modified version :

from functools import lru_cache

@lru_cache # a type of decorators

def increment(num):

   

    print(f'Running thousands line of code {num}')

    return num + 1

print(increment(1))

print(increment(2))

print(increment(3))

print(increment(1))

output :

Running thousands line of code 1 2 Running thousands line of code 2 3 Running thousands line of code 3 4 2 ⇠

Observed that 2 returns from the cache not from the function

Caution :

Using functools.lru_cache can cause memory leaks if it's used incorrectly, especially when applied to instance methods of a class.

I will make a separate post for incorrectly used and memory leaks :)